(-26x^2/35)/(39x/-40)

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Solution for (-26x^2/35)/(39x/-40) equation: 


D( x )

(39*x)/(-40) = 0

(39*x)/(-40) = 0

(39*x)/(-40) = 0

-39/40*x = 0 // : -39/40

x = 0

x in (-oo:0) U (0:+oo)

((-26*x^2)/35)/((39*x)/(-40)) = 0

16/21*x = 0 // : 16/21

x = 0

x in { 0} 

x belongs to the empty set

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